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DiameterOfBinaryTree.java
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/*
Given the root of a binary tree, return the length of the diameter of the tree.
The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
The length of a path between two nodes is represented by the number of edges between them.
Example 1:
Input: root = [1,2,3,4,5]
Output: 3
Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3].
*/
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;
public class DiameterOfBinaryTree {
public static void main(String[] args) {
TreeNode root=new TreeNode(1);
root.left=new TreeNode(2);
root.right=new TreeNode(3);
root.left.left=new TreeNode(4);
int ans = diameterOfBinaryTree(root);
System.out.println(ans);
}
public static int diameterOfBinaryTree(TreeNode root) {
List<Integer> result = new ArrayList<>();
if (root == null) {
return 0;
}
Queue<TreeNode> queue = new LinkedList<>();
queue.offer(root);
while (!queue.isEmpty()) {
int levelSize = queue.size();
for (int i = 0; i < levelSize; i++) {
TreeNode cur = queue.poll();
int leftDepth = maxDepth(cur.left);
int rightDepth = maxDepth(cur.right);
result.add(leftDepth + rightDepth);
if (cur.left != null) {
queue.offer(cur.left);
}
if (cur.right != null) {
queue.offer(cur.right);
}
}
}
int max = Integer.MIN_VALUE;
for (int num : result) {
if (num > max) {
max = num;
}
}
return max;
}
public static int maxDepth(TreeNode root) {
if (root == null) {
return 0;
}
return 1 + Math.max(maxDepth(root.left), maxDepth(root.right));
}
}