Detect Loop in linked list.cpp

/*
Detect Loop in linked list
==========================

Given a linked list of N nodes. The task is to check if the linked list has a loop. Linked list can contain self loop.

Example 1:
Input:
N = 3
value[] = {1,3,4}
x = 2
Output: True
Explanation: In above test case N = 3.
The linked list with nodes N = 3 is
given. Then value of x=2 is given which
means last node is connected with xth
node of linked list. Therefore, there
exists a loop.

Example 2:
Input:
N = 4
value[] = {1,8,3,4}
x = 0
Output: False
Explanation: For N = 4 ,x = 0 means
then lastNode->next = NULL, then
the Linked list does not contains
any loop.
Your Task:
The task is to complete the function detectloop() which contains reference to the head as only argument. This function should return 1 if linked list contains loop, else return 0.

Expected Time Complexity: O(N)
Expected Auxiliary Space: O(1)

Constraints:
1 <= N <= 104
1 <= Data on Node <= 103
*/

bool detectLoop(Node *head)
{
  Node *fast = head, *slow = head;
  while (fast && fast->next)
  {
    fast = fast->next->next;
    slow = slow->next;
    if (fast == slow)
      return true;
  }
  return false;
}