-
Notifications
You must be signed in to change notification settings - Fork 506
/
Copy pathCount and Say.cpp
64 lines (53 loc) · 1.59 KB
/
Count and Say.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
/*
Count and Say
=============
The count-and-say sequence is a sequence of digit strings defined by the recursive formula:
countAndSay(1) = "1"
countAndSay(n) is the way you would "say" the digit string from countAndSay(n-1), which is then converted into a different digit string.
To determine how you "say" a digit string, split it into the minimal number of groups so that each group is a contiguous section all of the same character. Then for each group, say the number of characters, then say the character. To convert the saying into a digit string, replace the counts with a number and concatenate every saying.
For example, the saying and conversion for digit string "3322251":
Given a positive integer n, return the nth term of the count-and-say sequence.
Example 1:
Input: n = 1
Output: "1"
Explanation: This is the base case.
Example 2:
Input: n = 4
Output: "1211"
Explanation:
countAndSay(1) = "1"
countAndSay(2) = say "1" = one 1 = "11"
countAndSay(3) = say "11" = two 1's = "21"
countAndSay(4) = say "21" = one 2 + one 1 = "12" + "11" = "1211"
Constraints:
1 <= n <= 30
*/
class Solution
{
public:
string countAndSay(int n)
{
if (n == 1)
return "1";
auto prev_ans = countAndSay(n - 1);
string ans = "";
int N = prev_ans.size(), count = 1;
for (int i = 0; i < N; ++i)
{
if (i == N - 1)
{
ans += to_string(count);
ans += prev_ans[i];
}
else if (prev_ans[i] == prev_ans[i + 1])
count++;
else
{
ans += to_string(count);
ans += prev_ans[i];
count = 1;
}
}
return ans;
}
};