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hello ! I'm having this geometry problem: H is the orthocenter of triangle ABC. The points D and E on the AC side are as follows,
that AD = DH, CE = EH. The lines BP and UR intersect the sides BC and AB at points P and Q
, respectively. The circumscribed circles of triangles BP and BP intersect the sides AB and
In C, at points X and y, respectively. Prove that the centers of the circumscribed circles of the triangles are
QHA and PHP lie on a straight XY.
And i have some troubles, for example how can denote the othocenter or write, that triangles are
QHA and PHP lie on a straight XY.
Help me please :( i even ready to pay money (if u'll send the alphageomtry's solution)
The text was updated successfully, but these errors were encountered:
What are the Points U and R?
How can BP intersect BC at Point P and not B? -> You use P to define P.
You want that a triangle lies on a straight line? But than it is no triangle anymore.
How can PHP be a triangle, if two Points are the same?
You need to fix the statement before someone can help you.
hello ! I'm having this geometry problem: H is the orthocenter of triangle ABC. The points D and E on the AC side are as follows,
that AD = DH, CE = EH. The lines BP and UR intersect the sides BC and AB at points P and Q
, respectively. The circumscribed circles of triangles BP and BP intersect the sides AB and
In C, at points X and y, respectively. Prove that the centers of the circumscribed circles of the triangles are
QHA and PHP lie on a straight XY.
And i have some troubles, for example how can denote the othocenter or write, that triangles are
QHA and PHP lie on a straight XY.
Help me please :( i even ready to pay money (if u'll send the alphageomtry's solution)
The text was updated successfully, but these errors were encountered: