frpc.toml 配置文件失败

[super-fsy]

Bug Description

（公网ip）服务器 A ：docker_container 中的 frpc.toml
bindport = 14108
frpc.toml:
serverAddr = "x, x, x, x"
serverPort = 14108
（内网ip）服务器 B ：frps.toml
[[proxies]]
name = "ssh"
type = "tcp"
localIP = "127.0.0.1"
localPort = 22
remotePort = 6000

frpc Version

frp_0.61.1

frps Version

frp_0.61.1

System Architecture

linux/amd64

Configurations

./frps -c frps.toml ok

./frpc -c frpc.toml always error

Logs

No response

Steps to reproduce

...

Affected area

• Docs
• Installation
• Performance and Scalability
• Security
• User Experience
• Test and Release
• Developer Infrastructure
• Client Plugin
• Server Plugin
• Extensions
• Others

[xqzr]

#3778 (comment)

[super-fsy]

#3778 (comment)

感谢您的回复 我这边试了下指令。
若使用 serverAddr=""
login to the server failed: dial tcp: lookup <x.x.x.x>: no such host. With loginFailExit enabled, no additional retries will be attempted
增加一行 transport.protocol="quic"

无法连接成功，个人感觉是frps.toml配置问题
我的frps.toml写在公网机器上 但是个人没有sudo权限，所以配置在个人创建的容器里面
容器配置如下：

同时公网ip机器只有一个端口是对外暴露 例如14108
所以连接公网机器可通过 ssh 用户名@x.x.x.x -p 14108 ,别的端口均未开放
求问如何配置容器里frps.toml
当前 frps.toml
bindport = 14108 # 监听端口，内网穿透通信的入口
auth.token = "581038" # 认证令牌

下面是frpc.toml
serverAddr = "x.x.x.x" # 公网机器的IP地址
serverPort = 14108 # 公网机器的 frps 服务监听端口
auth.token = "581038"
transport.protocol="quic"

[[proxies]]
name = "ssh"
type = "tcp"
localIP = "127.0.0.1"
localPort = 22
remotePort = 6000
期待您的回复