Reverso de um numero.ipynb

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      "==================================================\n",
      "\n",
      "Digite um numero: 598746\n",
      "647895\n",
      "\n",
      "==================================================\n"
     ]
    }
   ],
   "source": [
    "#Giovanni Andretta Carbonero\n",
    "\n",
    "#Função que recebe um valor inteiro e o inverte\n",
    "def reverso(rev):\n",
    "    inverte = str(rev)\n",
    "    return inverte[::-1]\n",
    "\n",
    "#Função principal\n",
    "def main():\n",
    "    \n",
    "    print(\"=\"*50 + \"\\n\")\n",
    "    \n",
    "    num = int(input(\"Digite um numero: \"))\n",
    "    print(reverso(num))\n",
    "    \n",
    "    print(\"\\n\" + \"=\"*50)\n",
    "    \n",
    "    \n",
    "main()"
   ]
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