-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathMerge_K_Sorted_Lists.cpp
59 lines (56 loc) · 1.57 KB
/
Merge_K_Sorted_Lists.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
// Merge k sorted linked lists and return it as one sorted list.
// Analyze and describe its complexity.
class Solution {
public:
// merge 2 lists: O(min(len(l1), len(l2)))
// merge K lists: O(total_length)
ListNode *mergeKLists(vector<ListNode *> &lists) {
if (lists.empty())
return NULL;
ListNode *head = lists[0];
for (int i = 1; i < lists.size(); i++) {
head = mergeTwoLists(head, lists[i]);
}
return head;
}
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
if (l1 == NULL & l2 == NULL)
return NULL;
if (l1 == NULL)
return l2;
if (l2 == NULL)
return l1;
ListNode *merge;
ListNode *head;
if (l1->val < l2->val) {
head = new ListNode(l1->val);
l1 = l1->next;
}
else {
head = new ListNode(l2->val);
l2 = l2->next;
}
merge = head;
while (l1 != NULL || l2 != NULL) {
if (l1 == NULL) {
merge->next = l2;
break;
}
if (l2 == NULL) {
merge->next = l1;
break;
}
if (l1->val < l2->val) {
merge->next = new ListNode(l1->val);
merge = merge->next;
l1 = l1->next;
}
else {
merge->next = new ListNode(l2->val);
merge = merge->next;
l2 = l2->next;
}
}
return head;
}
};\