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4Sum.cpp
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// Given an array S of n integers, are there elements a, b, c, and d in S
// such that a + b + c + d = target? Find all unique quadruplets in the
// array which gives the sum of target.
// Note:
// Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie,
// a ≤ b ≤ c ≤ d) The solution set must not contain duplicate quadruplets.
// For example, given array S = {1 0 -1 0 -2 2}, and target = 0.
// A solution set is:
// (-1, 0, 0, 1)
// (-2, -1, 1, 2)
// (-2, 0, 0, 2)
class Solution {
public:
vector<vector<int> > fourSum(vector<int> &num, int target) {
vector<vector<int> > ret;
vector<int> item;
if (num.empty())
return ret;
sort(num.begin(), num.end());
for (int i = 0; i < num.size(); i++) {
if (i > 0 && num[i] == num[i-1]) // avoid duplicates
continue;
for (int j = num.size()-1; j > i; j--) {
if (j < num.size()-1 && num[j] == num[j+1]) // ditto
continue;
int start = i + 1, end = j - 1;
while (start < end) {
int sum = num[i] + num[j] + num[start] + num[end];
if (start > i+1 && num[start] == num[start-1]) {
start++;
} else if (end < j-1 && num[end] == num[end+1]) {
end--;
} else {
if (sum == target) {
item.push_back(num[i]);
item.push_back(num[start]);
item.push_back(num[end]);
item.push_back(num[j]);
ret.push_back(item);
item.clear();
start++;
end--;
} else if (sum < target) {
start++;
} else {
end--;
}
}
}
}
}
return ret;
}
};